Interesting variable assigning in PHP

We commonly use the double $ sign to use the value of a variable as a variable name. For example

<?php$Jon = ‘Mrs. Merry’; $name = ‘Jon’; echo $$name ; // We can easily use to get the output “Mrs. Merry”; ?>

Now let’s have a fun.

<?php$name = ‘Jams’; $$name = ‘Jams Smith’; echo $$name; echo $Jams; ?>

What will be the out put. Easily we can evaluate it. Both $$name and $Jams will give same out put “Jams Smith”; Now yesterday I was reading the fundamentals of PHP. Lets see another example.

<? php$name = ‘Ja ms’; $$name = ‘Jams Smith’; echo $$name; echo $Ja ms; ?>

Now $Ja ms will generate a parser error. Because $Ja ms doesn’t follow the convention of variable declaration.

But what about $$name. Is it no confusing…..
But reality is $$name will print ‘Jams Smith’.
PHP manage $$name itself.